Class 10 Notes
  • Home
  • 10th Class Notes
    • Physics 10
    • Class 10 Notes
    • Pak Study 10th
    • CHEMISTRY 10 NOTES
    • Physics 10 Class
    • English Notes 10
    • Biology 10 Class
    • English Notes
    • Pak Study 10 Class
  • Articles
    • Education qoutes
    • DIT
  • English 4th Years
  • 9th Class Notes
    • Physics 9th
    • English 9th
    • Islamiat 9
  • Download file
  • Class 12 Notes
No Result
View All Result
  • Home
  • 10th Class Notes
    • Physics 10
    • Class 10 Notes
    • Pak Study 10th
    • CHEMISTRY 10 NOTES
    • Physics 10 Class
    • English Notes 10
    • Biology 10 Class
    • English Notes
    • Pak Study 10 Class
  • Articles
    • Education qoutes
    • DIT
  • English 4th Years
  • 9th Class Notes
    • Physics 9th
    • English 9th
    • Islamiat 9
  • Download file
  • Class 12 Notes
No Result
View All Result
Class 10 Notes
No Result
View All Result
Home Chemistry Notes

Sindh Class 9 Chemistry Notes Chapter 7 Solution and Suspension

September 15, 2021
in Chemistry Notes
0

Sindh and Karachi class 9th Chemistry notes chapter no 7 fill in the blanks, multiple-choice question, MCQs, and question answer.

Fill in the Blank Solution and Suspension

Table of Contents

  • Fill in the Blank Solution and Suspension
  • Multiple Choice Question Chemistry Chapter 7 Class 9th Notes – MCQs
  • Short question Solution and Suspension chemistry Class 9
    • Q.1) Define the following terms:
    • Q.2) Name the solute and solvent in the following solutions:
    • Q.3) Discuss the factors affecting the solubility. 
    • Q.4) Explain Why?
    • Q.5) Calculate molarity of solution containing 16 gm glucose per 300 ml solution. 
    • Q.6) Find the mass of sucrose (Molecular Mass=342) required to be dissolved per 600cm3 solution to prepare a semi-molar solution. 
    • Q.7) 5.3 gm Na2CO3 was dissolved in 800gm water, calculate the molality of solution. 
    • Q.8) It is desired to prepare 3 molal solution of NaOH. How much mass of it must be dissolved in 1500gm water. 
    • Q.9) Differentiate between
  1. The Component of sloutio present in smaller amount is called_____. Solute
  2. The component present in greater quantity is called ________. Solvent
  3. Soft drinks are the examples of gas in _______ Liquid
  4. When water is solvent solution is called __________ solution. aqueous
  5. The states of matter solid, liquid and gas produce ________ types of solutions on mixing. Nine
  6. Cloud and steam arce examples of liquid in ________ gas
  7. Smoke is solid in ________ gas
  8. The solubility of gases in a liquid decreases with the inverse in temperature.
  9. The Solubility of solids of solids and liquids arc ot affected by__________ Pressure.
  10. The Solubility of a gas in a liquid is directly proportional to the pressure gas. This is cllled _______ Henry’s Law.
  11. for crytallization supter ______________ is prepared. Saturated solution
  12. Solution is a _____________ of two or more substances. homogenous mixture
  13. The most common solvent in nature is _____________ . water
  14. An _ ___is the solution when the liquid solvent is water. aqueous solution
  15. 10% M/M solution contains 10 gram solute, dissolved in __ g solvent. 90
  16. _______________ is the symbol for the concentration unit of molarity. M

Read more: Sindh Class 9 Chemistry Notes Cha 6 States of Matter

Multiple Choice Question Chemistry Chapter 7 Class 9th Notes – MCQs

i) The suspended particles in suspensions are generally of the size. 

A. 10nmCorrectly unselected

B. 100nmIncorrectly selected

C. 1200nmIncorrectly unselected

D. 1nm

ii) The sum of the mole fractions of solute and solvent is equal to: 

A. 5

B. 2

C. 0

D. 1

iii) Solubility is defined as the amount of solute in gram at a given temperature, dissolved in _______of the solvent. 

A. 20g

B. 100g

C. 10g

D. 2000g

iv) The process in which a solid directly changes to vapors is known as: 

A. Sublimation

B. Evaporation

C. Diffusion

D. Fusion

v) The solubility of a gas ________with the rise in temperature. 

A. Increase 

B. Decrease

Short question Solution and Suspension chemistry Class 9

Q.1) Define the following terms:


a) Solute
b) Solvent
c) Solubility
d) Crystallization

Answer:
a) Solute
In a mixture solute is a substance which is dissolved in lesser amount in the solvent. For example, in a 5% glucose solution in water, solute is glucose and solvent is water.
b) Solvent
A solvent is a substance that dissolves a solute resulting in a solution. A solvent is usually a liquid but it can be gas or solid. For example, 10 ml alcohol is dissolved in water to make a solution. Here alcohol is solute in small amount and water is a solvent in greater quantity.
c) Solubility
The solubility of a substance is the amount of substance that dissolves in a given quantity of a solvent at a given temperature to produce a saturated solution. Solubility is usually expressed in grams of solute per 100 g of solvent.
d) Crystallization
The process in which dissolved solute comes out of solution and forms crystals is called crystallization.

Q.2) Name the solute and solvent in the following solutions:


a) Syrup
b) Haze (Dust in air)
c) Butter (Water in fat)
d) Fog
e) Jellies (Water in fruit pulp)
f) Smoke
g) Sodium amalgam
h) Cheese (Water in fat)
i) Foam (Water in air)
j) Mist

Answer:

Name of solution                Solute                                    Solvent    
SyrupSucroseWater
HazeDustAir
ButterWaterFat
FogWater vapourAir
JelliesWaterFruit pulp
SmokeCO2Air
Sodium amalgamMercurySodium
CheeseFatWater
FoamWaterAir
MistWaterAir

Q.3) Discuss the factors affecting the solubility. 

Answer:
There are some factors that affect the solubility of the solute in a solvent. These are:
i) Temperature:
Solubility of a solid in liquid increases with increase in temperature. For example solubility of sugar in water at 0°C is 179 g /100ml of water whereas at 100°C the solubility is 487g / 100 ml. This means the temperature has a profound effect on the solubility of a substance.
However, solubility of gases in a liquid decreases with the increase in temperature. For example when water is heated the small bubbles come out at the side of beaker. This shows that bubbles are composed of air. Since, air is less soluble in hot water than in cold water, air comes out in the form of bubbles.
ii) Pressure:
The solubilities of solids and liquids are not affected by pressure. But solubility of gas in liquid is affected by the pressure. Solubility of a gas in liquid is directly proportional to the pressure of a gas.
For example, soft drinks like coca cola and 7-up etc are bottled under increased pressure usually greater than 1 atm. When bottles are opened, pressure decreases, solubility of CO2 decreases, so bubbles of CO2 come out of solution. This is called Henry’s law,
m = KP
where m is the amount of gas dissolved.
iii) Nature of Solute and Solvent:
Solute and solvents obey the “like dissolve like” rule. Solute and solvent can be polar and non-polar. Polar and ionic solutes dissolve in polar solvents while non-polar solutes can easily dissolve in non-polar solvents.
For example, NaCl is polar solute so can easily be dissolved in polar water.

Q.4) Explain Why?

a) Common salt dissolves in water but not in petrol.
b) Cold drinks are bottled under a CO2 pressure greater than 1 atmosphere.
c) 100 ml solution of KNO3 can not hold more than 37gm of KNO3 in a dissolved state.

Answer:
a) Solute and solvents obey the like dissolve like a rule. Polar and ionic solutes are dissolved in polar solvents while non-polar solutes can easily dissolve in non-polar solvents. As NaCl is a polar solute, so can easily be dissolved in polar water. But it cannot dissolve in petrol because petrol is non-polar. When we mix them they do not show attractions.
b) Cold drinks like coca-cola and 7-up etc are bottled under increased pressure of CO2 usually greater than 1 atm. At this pressure sufficient amount of CO2 is dissolved in the solution. The solubility of a gas in a liquid is directly proportional to the pressure of a gas.
c) 100 ml solution of KNO3 cannot hold more than 37 g of KNO3 in the dissolved state because there is a limit to how much solute will dissolve in a given volume of solvent. If we add more than 37 g of KNO3 in 100 ml of water, the added salt will not dissolve, no matter how vigorously or how long we dissolve or stir it.

Q.5) Calculate molarity of solution containing 16 gm glucose per 300 ml solution. 

Answer:
Data:
Mass of glucose      = 16 g
Volume of solution = 300 ml
                                 = 300 / 1000 = 0.3 L
Molarity = ?
Solution:
Molar mass of glucose = 6 Ă— 12 + 12 Ă— 1 + 6 Ă— 16 = 180 g
Molarity                        = Mass of glucose / (Molar mass of glucose x Volume of solution)
                                       = 16 / (180 x 0.3) = 0.296 M

Q.6) Find the mass of sucrose (Molecular Mass=342) required to be dissolved per 600cm3 solution to prepare a semi-molar solution. 

Answer:
Data:
Molecular mass of sucrose   = 342 g
Volume of solution                = 600 cm3
Mass of sucrose                     = ?
Solution:
1000 ml of 1 molar solution contain = 342 g
1000 ml of .5 molar solution contain = 342 / 0.5 = 171 g
Thus,
1000 ml of solution contain    = 171 g
1 ml of solution contain           = 171 / 1000
600 ml of solution contain      = 171 / 1000 Ă— 600
                                                   = 102.6 g
Mass of sucrose                         = 102.6g
Thus,
102.6 g of sucrose is required to prepare the semi molar solution.

Q.7) 5.3 gm Na2CO3 was dissolved in 800gm water, calculate the molality of solution. 

Answer:
Data:
Mass of Na2CO3       = 5.3 g
Volume of Solvent   = 800 g
                                  = 800 / 1000 = 0.8 kg
Molarity = ?
Solution:
Molecular mass of Na2CO3     = 2 Ă— 23 + 1 Ă— 12 + 3 Ă—16 = 106
Molality                                    = Mass / (Gram formula mass x mass of solvent)
                                                  = 5.3 / (106 x 0.8)
                                                  = 0.0625 m

Q.8) It is desired to prepare 3 molal solution of NaOH. How much mass of it must be dissolved in 1500gm water. 

Answer:
Data:
Molality of solution     = 3 m
Volume of solution       = 1500 g
                                       = 1500 / 1000 = 1.5 kg
Mass of NaOH = ?
Solution:
Molecular mass of NaOH = 23 + 16 + 1 = 40
Molality                            = Mass of NaOH / (Molar mass of NaOH x Volume of solution)
Mass of NaOH                   = 3 x 40 x 1.5 = 18o g

Q.9) Differentiate between

a) Saturated and unsaturated solution,
b) Solution and suspension.

Answer:
a) Saturated and unsaturated solution

Saturated solutionUnsaturated solution
i) The solution contains the amount of solute as the capacity of the solvent.ii) The solution contains less amount of solute than the capacity of the solvent.
ii) Heating is required to dissolve further amount of solute.ii) Solute can be dissolved without heating.
iii) It is dynamic condition.iii) It is static condition.
iv) It is an example of equilibrium. iv) It is not the example of equilibrium.
chemistry notes chapter 7 solution and suspension pdf


SendShare234Tweet146Pin53Send

Related Posts

Sindh Class 9th Chemistry Notes Chapter 10 Chemical Energetics Pdf Download

Sindh Class 9th Chemistry Notes Chapter 10 Chemical Energetics Pdf Download

by admin
October 2, 2021
0

Chemistry class 9th Sindh Text board notes Chapter 10 Chemical Energetics Pdf Download. You can download the latest 9th Class...

Class 9 Sindh Chemistry Cha 9 Acids, Bases, and Salts Pdf Download

by admin
September 25, 2021
0

Chemistry Chapter 9 Acids, Bases, and Salts, Mcqs, fill in the blanks, multiple-choice question, and question-answer Pdf Download. Fill in...

Sindh Class 9 Chemistry Notes Chapter 8 Electrochemistry Mcqs, Question Pdf Download

by admin
September 24, 2021
0

Chemistry Class 9th Notes Chapter 8 Electrochemistry for Sindh & Karachi board, Mcqs, short questions, fill in the blank, and...

Please login to join discussion

  • KPK Board Class 10th English Book Notes
  • Unit 13 Hazrat Umar (RA) Class 10 English Notes
  • 10th class chemistry solved exercises chapter 12 pdf Download Hydrocarbons
  • English Notes Class 10 Unit 11
  • Computer science Notes Pdf Download all chapters
  • Unit 14 THE MODEL MILLIONAIRE Class 10 Notes
  • Unit 08 Women’s Role in the Pakistan Movement
  • Unit 1 Handwritten Class 10 English Notes
  • Sslr V2 Login | SSLR Local Application
  • KPK Physics Class 10 Notes Chapter 12 Geometrical Optics Conceptual Questions

Subscribe to Blog via Email

Enter your email address to subscribe to this blog and receive notifications of new posts by email.

Join 6 other subscribers

Categories

Archives

May 2022
M T W T F S S
 1
2345678
9101112131415
16171819202122
23242526272829
3031  
« Mar    
  • Home
  • 10th Class Notes
  • Articles
  • English 4th Years
  • 9th Class Notes
  • Download file

© 2022 JNews - Premium WordPress news & magazine theme by Jegtheme.

No Result
View All Result
  • Home
  • 10th Class Notes
    • Physics 10
    • Class 10 Notes
    • Pak Study 10th
    • CHEMISTRY 10 NOTES
    • Physics 10 Class
    • English Notes 10
    • Biology 10 Class
    • English Notes
    • Pak Study 10 Class
  • Articles
    • Education qoutes
    • DIT
  • English 4th Years
  • 9th Class Notes
    • Physics 9th
    • English 9th
    • Islamiat 9
  • Download file

© 2022 JNews - Premium WordPress news & magazine theme by Jegtheme.